r - Select only matching files using multiple patterns in list.files -

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i have following csv files , want select ones have matching 'pop' , 'throughput' values in each string:

example_pop_high_throughput_high_strategy.csv example_pop_high_throughput_base_strategy.csv example_pop_high_throughput_low_strategy.csv example_pop_base_throughput_high_strategy.csv example_pop_base_throughput_base_strategy.csv example_pop_base_throughput_low_strategy.csv example_pop_low_throughput_high_strategy.csv example_pop_low_throughput_base_strategy.csv example_pop_low_throughput_low_strategy.csv

i want these:

example_pop_high_throughput_high_strategy.csv                 example_pop_base_throughput_base_strategy.csv example_pop_low_throughput_low_strategy.csv

i can use list.files select files with, example, 'high':

file_names <- list.files("made/up/path", pattern = c("high"))

although, trying twice match 'high' , 'high', didn't work:

file_names <- list.files("made/up/path", pattern = c("high", "high"))

is there way select files matching 'pop' , 'throughput' values, preferably in single expression?

the following should work:

file_names <- list.files("made/up/path", pattern = c("(low|base|high).+\\1"))




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