angular - How to wait until one of many possible observables returns before continuing -

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i have switch statement makes different http call based on input.

it looks this:

switch(myobject.type){     case 'type1':         myobject.name = this.service1.getname(myobject.id);         break;     case 'type2':         myobject.name = this.service2.getname(myobject.id);         break;     case 'type3':         myobject.name = this.service3.getname(myobject.id);         break; }

and after these have statement save entry:

this.storageservice.saveentry(myobject);

but @ time entry saved, not have name property set.

what proper way wait 1 of these async calls return before saving entry?

if must use switch statement, perhaps have each branch return observable instead, set myobject.name in subscribe() or utilize operators such do , switchmap pass value this.storageservice.saveentry(). 

foo(): observable<any> {     switch(myobject.type){         case 'type1':             return this.service1.getname(myobject.id);             break;         case 'type2':             return this.service2.getname(myobject.id);             break;         case 'type3':             return this.service3.getname(myobject.id);             break;     } }  bar() {         foo()       .do(name => myobject.name = name)       .switchmap(name => this.storageservice.saveentry(myobject))       .subscribe(response => console.log(response); }

hopefully helps!





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