unix - Need to remove the extra empty lines from the output of shell script -

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i'm trying write code print files taking more min_size (lets 10g) in directory. problem output off below code files irrespective of min_size. getting other details mtime , owner later in code part doesnt work fine, whats wrong here ?

#!/bin/sh  if (( $# <3 ));   echo "$0 dirname min_size count"   exit 1 else   dirname="$1";   min_size="$2";   count="$3";   #shift 3 fi  tmpfile=$(mktemp /lawdump/pulkit/files.xxxxxx) exec 3> "$tmpfile" find "${dirname}" -type f -print0 2>&1 | grep -v "permission denied" | xargs -0 -i {} echo "{}" > "$tmpfile" in `cat tmpfile`   x="`du -ah $i | awk '{print $1}' | grep g | sort -nr -k 1`"   size=$(echo $x | sed 's/[a-za-z]*//g')   if [ size > $min_size ];then   echo $size fi done

note : know can done through find or du need write shell script have email sent out regularly details.





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