c# - how to Get input type file value from bootstrap model in mvc 5 controller using jquery ajax -

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i'm trying input type file value in mvc 5 c# controller unable value. i'm using bootstrap model , jquery ajax task. , dont use form submit this. following code.

bootstrap model code : 

<div class="modal-content">                 <div class="modal-header">                     <button type="button" class="close" data-dismiss="modal">&times;</button>                     <h4>mark chargeback</h4>                 </div>                 <div class="modal-body" align="center">                     <div>                         <input type="file" id="fdocs" class="form-control" style="margin-top: 5px;"/>                                                    <input type="submit" id="btngetdocs" class="btn btn-success" value="submit" style="margin-top: 5px;" />                     </div>                 </div>             </div>

jquery ajax code :

 $('#btngetdocs').click(function () {             var docs = $('#fdocs').val();             //alert(docs);                 $.ajax({                     type: "post",                     url: "../cs/getdocs",                     data: '{checkimg:"' + docs + '"}',                     mimetype: "multipart/form-data",                     contenttype: 'application/json',                     datatype: "json",                     success: function (data) {                         alert(data);                         $('#mymodal').modal('hide');                     },                     error: function () {                         alert(data);                     }                 });         });

mvc controller code :

        [httppost]         public actionresult getdocs(httppostedfilebase checkimg)         {             try             {                 int result = docs(checkimg);                 if (result > 0)                 {                     return json("docs upload successfully.");                 }                 else                 {                     return json("please try again.");                 }             }             catch (exception ex) { return json(ex.tostring()); }         }

so please rid me out problem.





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