python - Django, creating a functional search bar and search results page -

i'm having trouble working inherited code make functional search bar. i've been having trouble creating search_results page.

i stripped down search_results page having 1 line. search_results.html: <div>you searched {{ query }}</div> right now, search_results page doesn't render {{ query }}. no text user entered appears. shows on page "you searched for"

searchbox.html

<form class="search" action="{% url 'search' %}" method='post'>   {% csrf_token %}   <input type="search" placeholder="search here..." name="usr_query"        value='{{ query }}' required>   <button type="submit">search</button> </form> 

views.py

def search(request):   query = request.post['usr_query']   print "query: "   print query   t = loader.get_template('gtr_site/test_search_results.html')   c = context({ 'query': query,})   return httpresponse(t.render(c)) 

i getting little cautious , added "print" statement... , print out user enters in search bar. isn't being generated on search_results page.

whats reasoning this?

edit:

adding urls.py

urlpatterns = [     url(r'^$', views.index, name='index'),     url(r'^about/$', views.about, name='about'),     url(r'^contact/$', views.contact, name='contact'),     url(r'^search_engine/$', views.statement_search_engine, name='statement-search') # <- url searchbox.html,     url(r'^test_search_results/$', views.search, name='test-search'), # <- url searchresults.     url(r'^(?p<statement_id>.+)/$', views.statement_page, name='statement'), ] + static(settings.static_url, document_root=settings.static_root) 

change value='{{ request.get.usr_query }}' value="{{ query }}"

right forcing show parameter. works on initial page load (which typically get) @ point haven't done searching. submit search (properly in opinion, debatable) post. search function uses post parameter , returns in in context query, correct. display value of usr_query - not exist @ point because page posted page. change value= , should work.

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