javascript - Regex replace with captured -

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• using $0 refer entire match in javascript's string.replace 2 answers

i want replace non alphanumeric character in string self surrender "[" , "]".

i tried this:

var text = "ab!@1b*. ef"; var regex = /\w/g;  var result  = text.replace(regex, "[$0]");  console.log(result); 

i expecting get:

ab[!][@]1b[*][.][ ]ef

but instead get:

ab[$0][$0]1b[$0][$0][$0]ef

how can using javascript(node)?

you need wrap group in parentheses assign $1, this:

var text = "ab!@1b*. ef";  var regex = /(\w)/g;    var result  = text.replace(regex, "[$1]");    console.log(result);

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