Converting hex char string to unicode string (python) -
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i have string of unicode ordinals (in hex form) so:
\u063a\u064a\u0646\u064a\u0627
it's unicode repsentation of arabic string غينيا (gotten of arabic lorem ipsum generator).
i want convert unicode hex string غينيا. tried print u'%s' % "\u063a\u064a\u0646\u064a\u0627" (pointed out here) returns hex format, not symbols. print word.replace("\u","\\u") doesn't job either. do?
i'm not entirely sure question want, i'll cover both cases can see.
case 1: want output arabic string code, using unicode literal syntax. in case, should prefix string literal u , you'll right rain:
s = u"\u063a\u064a\u0646\u064a\u0627" print(s) this same as
print u'%s' % s except shorter. in case, formatting otherwise empty string formed string doesn't make sense, because it's not changing - in other words, u'%s' % s == s.
case 2: have escaped string other source want evaluate unicode string. kind of looks you're trying print u'%s' %. can done
import ast s = r"\u063a\u064a\u0646\u064a\u0627" print ast.literal_eval("u'{}'".format(s)) note unlike eval safe, literal_eval doesn't allow function call. see s here r-prefixed string, backslashes aren't escaping literally backslash characters.
both pieces of code correctly output
غينيا some elaboration on print u'%s' % s case 1. behaves differently, because if string has been escaped, won't evaluated unicode literal in formatting. because python builds unicode out of unicode literal-like expressions (such s) when @ first evaluated. if has been escaped, kind of out of reach using normal string operations, have use literal_eval evaluate again in order print string. when run
print u'%s' % s the output is
\u063a\u064a\u0646\u064a\u0627 note isn't representation of unicode object literally ascii string backslashes , characters.
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