shell - Bash command ls ordering options -

new here (and coding). i'm writing simple bash script helps me change character character in files of current directory. here's code:

#!/bin/bash #this script changes characters in files of current directory  num=$(ls -1 | wc -l | awk '{print $1}')  echo "there $num files in folder." echo "changing $1 $2 in names..." echo "done! here's happened:"  in $(seq 1 $num)     oldname=$(ls -1 | head -$i | tail -1)     newname=$(ls -1 | head -$i | tail -1 | sed -e "s/${1}/${2}/g")     mv -v "$oldname" "$newname" done 

so if write ./ccin.sh " " "_" should changing spaces in names of files in current directory underscores. except doesn't, , think ls's fault. for loop skipping on files because ls changes order according sorts files every time mv modifies 1 of them. need isolate names of files in way not rely on "last modified" property. thought of file size, won't work if there 2 files have same size – e.g., i'm trying code on directory full of empty files.

is there way sort files ls such remain in same order mv modifies names?

you can try substitute loop one:

find . -type f | while read file     oldname="$file"     newname=`echo $file| sed -e "s/${1}/${2}/g"`     mv -v "$oldname" "$newname" done 

instead of running ls multiple times in order file rename, run find once , iterate on results

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