javascript - Array filter with possible undefined properties -

i have array of objects may or not contain property.

so, in order filter it, this:

array = array.filter(v => v.myproperty != undefined); array = array.filter(v => v.myproperty[0] != undefined);

this removes ones myproperty undefined and, afterwards, ones first element inside myproperty.

is there way of having single liner prevents me applying filter array twice?

something like:

array = array.filter((v => v.myproperty || [])[0] != undefined);

what about:

filtered_array = array.filter(element => element.property && element.property[0]);

what condition evaluate left part first. if it's true, try evaluate right part , return result.

wiki

tL